We know that
Angle subtended by a chord on mayor area is half of that subtended on center
Hence
∠ADC= 1/2∠AOC
∠ADC= 1/2 ×130=65∘
ADCB is cyclic quadrilateral ⇒
Sum of opposite Angles is 180º
∠ABC+∠ADC=180º
∠ABC+65=180º
∠ABC= 115º
We know that
Angle subtended by a chord on mayor area is half of that subtended on center
Hence
∠ADC= 1/2∠AOC
∠ADC= 1/2 ×130=65∘
ADCB is cyclic quadrilateral ⇒
Sum of opposite Angles is 180º
∠ABC+∠ADC=180º
∠ABC+65=180º
∠ABC= 115º
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